1,104x^2=50

Solution for 1,104x^2=50 equation:

1.104x^2=50

We move all terms to the left:

1.104x^2-(50)=0

a = 1.104; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·1.104·(-50)
Δ = 220.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{220.8}}{2*1.104}=\frac{0-\sqrt{220.8}}{2.208}
=-\frac{\sqrt{}}{2.208}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{220.8}}{2*1.104}=\frac{0+\sqrt{220.8}}{2.208}
=\frac{\sqrt{}}{2.208}
$